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| 1 | Any parallel circuit is a current divider in which the individual branch currents are inversely proportional to the branch resistance values. |
 | A) | True |
| B) | False |
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| 2 | A series string can be considered a current divider. |
| A) | True |
| B) | False |
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| 3 | Since series voltage drops are proportional to the resistances, and then a very small R in series with a much larger R has a negligible IR drop. |
| A) | True |
| B) | False |
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| 4 | In a two branch, parallel circuit, once one current is calculated, the other can be found by subtracting the calculated current from the total current (IT). |
| A) | True |
| B) | False |
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| 5 | With parallel branches, a higher resistance takes more branch current. |
| A) | True |
| B) | False |
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| 6 | The current divider formula can be used for more than two branch resistances. |
| A) | True |
| B) | False |
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| 7 | Conductance and current are directly proportional. |
| A) | True |
| B) | False |
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| 8 | The unit for G is the watt-second. |
| A) | True |
| B) | False |
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| 9 | In a series voltage divider, the IR drops add up to equal the applied voltage. |
| A) | True |
| B) | False |
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| 10 | All in a voltage divider must come from the voltage source. |
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| 11 | The current through all resistances in a voltage divider is current. |
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| 12 | The bleeder current that flows through an entire divider is generally specified at about % of the load current. |
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| 13 | A loaded voltage divider is just a practical application of a circuit. |
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| 14 | When parallel-connected loads are added to a series circuit, the circuit becomes a(n) voltage divider. |
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| 15 | In a series voltage divider, the points at which different voltages are available are called . |
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| 16 | Any series circuit is a voltage divider in which the individual resistor voltage drops are to the series resistance values. |
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| 17 | In a divider, each branch current is inversely proportional to its R. |
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| 18 | Any series circuit in which the individual resistor voltage drops are proportional to the series resistance values is a(n) |
| A) | balanced bridge |
| B) | unbalanced bridge |
| C) | current divider |
| D) | voltage divider |
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| 19 | In a series circuit, the voltage drops equal |
| A) | the sum of I and R |
| B) | the product of I times R |
| C) | the power divided by voltage |
| D) | the current times the applied voltage |
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| 20 | In a parallel circuit, currents |
| A) | divide inversely as the branch resistances |
| B) | divide proportionally as the branch currents |
| C) | are always equal in all branches |
| D) | are equal to power divided by R |
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| 21 | Conductance G is equal to |
| A) | 1/T |
| B) | R times S |
| C) | 1/R |
| D) | I squared R |
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| 22 | The unit for G is the |
| A) | ohm |
| B) | joule |
| C) | coulomb |
| D) | siemens |
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| 23 | In a series circuit, the IR drops |
| A) | add to equal the applied voltage |
| B) | will cancel out |
| C) | all equal zero |
| D) | add to equal twice the applied voltage |
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| 24 | In a current divider with two branch resistances, the larger R |
| A) | has more current |
| B) | has less current |
| C) | has more voltage |
| D) | has less voltage |
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| 25 | The current divider formula can be used |
| A) | with series circuits |
| B) | for any number of branch resistances |
| C) | only for two branch resistances |
| D) | to solve for applied voltage |