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| 1 | |
Waiting lines will never form in a service facility, if the overall system capacity is much more than overall processing requirements. |
| | A) | True |
| | B) | False |
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| 2 | |
Variability in demand and/or time to service is the main reason for formation of waiting lines in front of service facilities. |
| | A) | True |
| | B) | False |
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| 3 | |
If the overall system capacity is less than the overall processing requirements, and if the facility is open continuously, then very long waiting lines will be formed as time passes. |
| | A) | True |
| | B) | False |
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| 4 | |
The combined cost of service capacity and customer waiting cost is generally U shaped. |
| | A) | True |
| | B) | False |
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| 5 | |
Customers arrive at a bus station at the rate of 5 per minute following Poisson distribution. If one looks at the distribution of inter-arrival times of customers, it would also follow Poisson distribution. |
| | A) | True |
| | B) | False |
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| 6 | |
Customers arrive at a bus station at the rate of 5 per minute following Poisson distribution. What is the probability of 3 arrivals in a one-minute interval? |
| | A) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=gif::::/sites/dl/free/007299066x/335683/013_06_a.gif','popWin', 'width=85,height=103,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>]]> |
| | B) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=gif::::/sites/dl/free/007299066x/335683/013_06_b.gif','popWin', 'width=85,height=103,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>]]> |
| | C) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=gif::::/sites/dl/free/007299066x/335683/013_06_c.gif','popWin', 'width=85,height=103,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>]]> |
| | D) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=gif::::/sites/dl/free/007299066x/335683/013_06_d.gif','popWin', 'width=85,height=103,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>]]> |
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| 7 | |
Time between consecutive arrivals of customers to a grocery store is exponential with a rate of 3 per minute. What is the probability that a time of 2 minutes will elapse between the arrivals of two consecutive customers? |
| | A) | e-6 |
| | B) | e-3 |
| | C) | 1 - e-6 |
| | D) | 1 - e-3 |
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| 8 | |
Two key parameters in any single channel single phase queuing system are: |
| | A) | Waiting time and service time. |
| | B) | Arrival rate and number of servers. |
| | C) | System utilization and average queue length. |
| | D) | Mean arrival rate and mean service rate. |
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| 9 | |
In a single channel manual soft cloth wash, cars arrive following the Poisson distribution at the rate of 8 per hour. It takes an average of 6 minutes to wash a car and the service time follows exponential distribution. The system utilization would be |
| | A) | 75% |
| | B) | 80% |
| | C) | 133.33% |
| | D) | 125% |
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| 10 | |
In a single channel manual soft cloth wash, cars arrive following the Poisson distribution at the rate of 8 per hour. It takes an average of 6 minutes to wash a car and the service time follows exponential distribution. The average number of cars in the system will be: |
| | A) | 0.8 |
| | B) | 3.2 |
| | C) | 5 |
| | D) | 4 |
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| 11 | |
A grocery store has two identical checkouts each can serve an average of 20 customers per hour following an exponential distribution. Customers ready to checkout arrive at a common checkout line following Poisson distribution with a rate of 30 per hour. For this system, it is known that Lq = 1.929 and P0 = 0.143. The average number in the system will be: |
| | A) | 1.929 |
| | B) | 2.072 |
| | C) | 1.643 |
| | D) | 3.429 |
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| 12 | |
In Mr. and Mrs. Phillips Grocery Store, customers join the single checkout line following the Poisson distribution at a rate of 15 per hour. The checkout clerk can handle 20 customers per hour and the service time follows the exponential distribution. The average number in the queue (Lq) = 2.25 and utilization is 0.75. The maximum number of customers waiting in line with a probability of 0.95 will be: |
| | A) | 8 |
| | B) | 9 |
| | C) | 18 |
| | D) | 19 |
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